What Is The Sum Of The First 30 Terms Of This Arithmetic Sequence 6, 13, 20, 27, 34, …? (Solution)

Summary: The sum of the first 30 terms of this arithmetic sequence 6, 13, 20, 27, 34, … is 3225.

What is the algebraic expression of the arithmetic sequence 6 13 20?

This is an arithmetic sequence since there is a common difference between each term. In this case, adding 7 to the previous term in the sequence gives the next term. In other words, an=a1+d(n−1) a n = a 1 + d ( n – 1 ). This is the formula of an arithmetic sequence.

What is the 30th term of the arithmetic sequence?

The 30th term of the arithmetic progression is 91.

How do you find the sum of the terms in an arithmetic sequence?

The terms between given terms of an arithmetic sequence. The sum of the terms of an arithmetic sequence. The sum of the first n terms of an arithmetic sequence given by the formula: Sn=n(a1+an)2.

What is the sum of the first 30 terms of the sequence an 6n 5?

The sum of the first 30 terms of the sequence an = 6n + 5 is. a3 = 6(3) + 5 = 23 and so on…

What is the sum of the first 20 terms in an arithmetic sequence?

The sum of the first 20 terms of an arithmetic sequence is 550. Given it has first term equal to −2, find the value of the common difference d.

What is the nth term?

What is the nth term? The nth term is a formula that enables us to find any term in a sequence. The ‘n’ stands for the term number. We can make a sequence using the nth term by substituting different values for the term number(n).

What do we call the sum of a sequence of numbers?

The sum of the terms of a sequence is called a series. If a sequence is arithmetic or geometric there are formulas to find the sum of the first n terms, denoted Sn, without actually adding all of the terms.

What is the 32 term of the arithmetic sequence?

We now apply the formula for the nth term of an arithmetic sequence to determine the 32nd term. tn=a+(n−1)d. t32=−32+(32−1)−11. t32=−32−341. t32= 373.

How do you find the 30th term of AP?

The correct option is c = – 77. Thus, 30th term of the AP is – 77.

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Solve 6,13,20,27,34 Tiger Algebra Solver

The numbers 6, 13, 20, 27, and 34 in your input appear to be an arithmetic sequence.

Find the difference between the members

  • A 2 minus a 1 equals 13-6= 7
  • A 3 minus a 2 equals 20-13 = 7
  • A 4 -a 3 =27-20=7
  • A 4 -a 3 =27-20=7
  • A 5 minus a 4 =34-27=7

The difference between each pair of adjacent members in the series is constant and equal to seven points.

General Form: a n =a 1 +(n-1)d

A 1 equals 6. (this is the 1st member) a n =34 (this is the 34th member of the group) d=7 is a prime number (this is the difference between consecutive members) n = 5 (this is the number of members)

Sum of finite series members

An arithmetic series is a collection of components of a finite arithmetic progression that are added together. Consider the following total, which is based on our example: 6+13+20+27+34 If you know the number of words being added (in this case 5), multiply that number by the sum of the first and final numbers in the progression (in this case 6 + 34 = 40), and divide the result by two: 5(6+34) = 40. 2 The total of the five parts of this series equals one hundred. This series corresponds to the straight liney=7x+6 in the following equation:

Finding the n thelement

  • A 1 equals a 1 plus (n-1) *d is greater than six (1-1) *7 equals 6
  • A 2 equals a 1 plus (n-1) *d is greater than six (2-1) *7 equals 13
  • A 3 equals a 1 plus (n-1) *d is greater than six (3-1) *7 equals 20
  • A 4 equals a 1 plus (n-1) *d is greater than six (4-1) *7 equals 27
  • A 5 equals a 1 plus (n-1) *d is greater than six (5-1) *7 equals 34
  • A 6 equals a 1 plus (n-1) *d is greater than six (6-1) *7 equals 41
  • A 7 equals a 1 plus (n-1) *d is greater than six (7-1) *7 equals 48
  • An 8 equals a 1 plus (n-1) *d is greater than six (8-1) A 7 equals 55
  • A 9 equals a 1 plus (n-1) *d is greater than six (9-1) *7 =62
  • A 10=a 1 +(n-1)*d =6+
  • A 10=a 1 +(n-1)*d =6+ (10-1) *7 =69
  • An 11=a 1 +(n-1)*d =6+
  • An 11=a 1 +(n-1)*d =6+ (11-1) *7 equals 76
  • A 12 equals a 1 plus (n-1) *d is greater than six (12-1) A 7 equals 83
  • A 13 equals a 1 plus (n-1) *d is greater than six (13-1) *7 =90
  • A 14=a 1 +(n-1)*d =6+
  • A 14=a 1 +(n-1)*d =6+ (14-1) *7 =97
  • A 15=a 1 +(n-1)*d =6+
  • A 15=a 1 +(n-1)*d =6+ (15-1) *7 equals 104
  • A 16 equals a 1 plus (n-1) *d is greater than six (16-1) *7 =111
  • A 17=a 1 +(n-1)*d =6+
  • A 17=a 1 +(n-1)*d =6+ (17-1) *7 equals 118
  • An 18 equals a 1 plus (n-1) *d is greater than six (18-1) *7 equals 125
  • A 19 equals a 1 plus (n-1) *d is greater than six (19-1) *7 equals 132
  • A 20 equals a 1 plus (n-1) *d is greater than six (20-1) *7 equals 139
  • A 21 equals a 1 plus (n-1) *d is greater than six (21-1) *7 equals 146
  • A 22 equals a 1 plus (n-1) *d is greater than six (22-1) *7 equals 153
  • A 23 equals a 1 plus (n-1) *d is greater than six (23-1) The number 7 equals 160
  • The number 24 equals 1 plus (n-1) *d is greater than six (24-1) *7 =167
  • A 25=a 1 +(n-1)*d =6+
  • A 25=a 1 +(n-1)*d =6+ (25-1) *7 =174
  • A 26=a 1 +(n-1)*d =6+
  • A 26=a 1 +(n-1)*d =6+ (26-1) *7 equals 181
  • A 27 equals a 1 plus (n-1) *d is greater than six (27-1) *7 =188
  • A 28=a 1 +(n-1)*d =6+
  • A 28=a 1 +(n-1)*d =6+ (28-1) *7 =195
  • A 29=a 1 +(n-1)*d =6+
  • A 29=a 1 +(n-1)*d =6+ (29-1) *7 =202
  • A 30=a 1 +(n-1)*d =6+
  • A 30=a 1 +(n-1)*d =6+ (30-1) *7 = 209 points
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Solve 6,13,20,27,34,41,48,55 Tiger Algebra Solver

The numbers 6, 13, 20, 27, 34, 41, 48, and 55 in your input appear to represent an arithmetic sequence.

Find the difference between the members

  • The following are the results of the following calculations: A 2 + A 1 =13-6= 7
  • A 3 + A 2 =20-13= 7
  • A 4 + A 3 =27-20= 7
  • A 5 -a 4 =34-27= 7
  • A 6 -a 5 =48-41= 7
  • A 8 -a 7 =55-48= 7
  • A 9 -a 7 =55-48= 7

The difference between each pair of adjacent members in the series is constant and equal to seven points.

General Form: a n =a 1 +(n-1)d

A 1 equals 6. (this is the 1st member) a n =55 (this is the 55th member of the group) d=7 is a prime number (this is the difference between consecutive members) n=8 is the number of participants (this is the number of members)

Sum of finite series members

An arithmetic series is a collection of components of a finite arithmetic progression that are added together. Consider the following total, which is based on our example: 6+13+20+27+34+41+48+55 If you know the number of words being added (in this case 8), multiply that number by the sum of the first and final numbers in the progression (in this case 6 + 55 = 61), and divide the result by two: 8(6+55) = 61. 2 The total of the eight members in this series is 244 in number of members. This series corresponds to the straight liney=7x+6 in the following equation:

Finding the n thelement

  • A 1 equals a 1 plus (n-1) *d is greater than six (1-1) *7 equals 6
  • A 2 equals a 1 plus (n-1) *d is greater than six (2-1) *7 equals 13
  • A 3 equals a 1 plus (n-1) *d is greater than six (3-1) *7 equals 20
  • A 4 equals a 1 plus (n-1) *d is greater than six (4-1) *7 equals 27
  • A 5 equals a 1 plus (n-1) *d is greater than six (5-1) *7 equals 34
  • A 6 equals a 1 plus (n-1) *d is greater than six (6-1) *7 equals 41
  • A 7 equals a 1 plus (n-1) *d is greater than six (7-1) *7 equals 48
  • An 8 equals a 1 plus (n-1) *d is greater than six (8-1) A 7 equals 55
  • A 9 equals a 1 plus (n-1) *d is greater than six (9-1) *7 =62
  • A 10=a 1 +(n-1)*d =6+
  • A 10=a 1 +(n-1)*d =6+ (10-1) *7 =69
  • An 11=a 1 +(n-1)*d =6+
  • An 11=a 1 +(n-1)*d =6+ (11-1) *7 equals 76
  • A 12 equals a 1 plus (n-1) *d is greater than six (12-1) A 7 equals 83
  • A 13 equals a 1 plus (n-1) *d is greater than six (13-1) *7 =90
  • A 14=a 1 +(n-1)*d =6+
  • A 14=a 1 +(n-1)*d =6+ (14-1) *7 =97
  • A 15=a 1 +(n-1)*d =6+
  • A 15=a 1 +(n-1)*d =6+ (15-1) *7 equals 104
  • A 16 equals a 1 plus (n-1) *d is greater than six (16-1) *7 =111
  • A 17=a 1 +(n-1)*d =6+
  • A 17=a 1 +(n-1)*d =6+ (17-1) *7 equals 118
  • An 18 equals a 1 plus (n-1) *d is greater than six (18-1) *7 equals 125
  • A 19 equals a 1 plus (n-1) *d is greater than six (19-1) *7 equals 132
  • A 20 equals a 1 plus (n-1) *d is greater than six (20-1) *7 equals 139
  • A 21 equals a 1 plus (n-1) *d is greater than six (21-1) *7 equals 146
  • A 22 equals a 1 plus (n-1) *d is greater than six (22-1) *7 equals 153
  • A 23 equals a 1 plus (n-1) *d is greater than six (23-1) The number 7 equals 160
  • The number 24 equals 1 plus (n-1) *d is greater than six (24-1) *7 =167
  • A 25=a 1 +(n-1)*d =6+
  • A 25=a 1 +(n-1)*d =6+ (25-1) *7 =174
  • A 26=a 1 +(n-1)*d =6+
  • A 26=a 1 +(n-1)*d =6+ (26-1) *7 equals 181
  • A 27 equals a 1 plus (n-1) *d is greater than six (27-1) *7 equals 188
  • A 28 equals a 1 plus (n-1) *d is greater than six (28-1) *7 =195
  • A 29=a 1 +(n-1)*d =6+
  • A 29=a 1 +(n-1)*d =6+ (29-1) *7 =202
  • A 30=a 1 +(n-1)*d =6+
  • A 30=a 1 +(n-1)*d =6+ (30-1) *7 =209
  • A 31=a 1 +(n-1)*d =6+(31-1)*7 =216
  • A 32=a 1 +(n-1)*d =6+(31-1)*7 =216
  • A 33=a 1 +(n-1)*d =6+(33-1)*7 =216
  • A 34=a 1 +(n-1)*d =6+(34-1)*7 =216
  • A 35=a 1 + (32-1) *7 =223
  • A 33=a 1 +(n-1)*d =6+(33-1)*7 =230
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How to find the next term in an arithmetic sequence – Algebra 1

1. A 1 is equal to 1. (n-1) D is more than six (1-1) The number 7 equals 6, and a 2 equals a 1 plus (n-1) D is more than six (2-1) The number 7 equals 13; a 3 equals a 1 plus (n-1) D is more than six (3-1) The number 7 equals twenty; a 4 equals one plus (n-1) D is more than six (4-1) The number 7 equals 27; a 5 equals a 1 plus (n-1) D is more than six (5-1) The number 7 equals 34; a 6 is equal to a 1. (n-1) D is more than six (6-1) *7 equals 41; a 7 equals a 1 plus a (n-1) D is more than six (7-1) The number 7 equals 48; the number 8 equals one plus (n-1) D is more than six (8-1) The number 7 is equal to 55; the number 9 is equal to 1.

The answer is a 31 = a 1 +(n-1)*d =6+(31-1)*7 =216; the answer is a 32 = a 1 +(n-1)*d =6+(31-1)*7 =216; the answer is a 32= a 1 +(n-1)*d =6+(31-1)*7 =216; the answer is a 31 = a 1 +(n-1)*d =6+( (32-1) *7 =223; a 33=a 1 + (n-1)*d =6+(33-1)*7 =230; a 33=a 1 + (n-1)*d =6+(33-1)*7 =230; a 33=a 1 + (n-1)*d =6+(33-1)*7 =230;

What is the sum of the first 30 terms of this arithmetic sequence? 6, 13, 20, 27, 34, …

The coordinate plan (-6,9) b (3,9) c (3,3) def is illustrated in the coordinate plan below, which is the coordinate plan (-6,9) b (3,9) c (3,3) def. Mathematics on the 21st of June, 2019 at 13:30 Please note that the question is depicted in the image! . Mathematics on the 21st of June, 2019 at 14:30 A scientist wishes to utilize a model to convey the findings of a rigorous scientific inquiry that he has conducted. What are the benefits of using a model? a)Because the model helps understanding the topics more straightforward for you.

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