The 32^{nd} term of the arithmetic sequence where a_{1} = -31 and a_{9} = -119 is a** _{32} = -372**.

Contents

- 1 What is the 32nd term of the arithmetic sequence where a1 and a9?
- 2 What is the 32nd term of the arithmetic sequence where a1 14 and a13 − 58?
- 3 What is the 32nd term of the arithmetic sequence where a1 =- 33?
- 4 What is the 32nd term of the arithmetic sequence where a1?
- 5 What is a1 in an arithmetic sequence?
- 6 How do you use the formula a1 + N 1 D?
- 7 What is the 32nd term of the arithmetic sequence where a1 13 and a13 − 59 1 point?
- 8 What is the 32nd term of the arithmetic sequence where a1 12 and a13 − 60?
- 9 What is the 32nd te…
- 10 What is the 32nd term of the arithmetic sequence where a1 = −31 and a9 = −119? −372 −361 −350 −339?
- 11 What is the 32nd term of the arithmetic sequence where a1 = –31 and a9 = –119?
- 12 How to find the nth term of an arithmetic sequence – Algebra 1
- 13 Arithmetic Sequences and Series

## What is the 32nd term of the arithmetic sequence where a1 and a9?

The 32nd term of the arithmetic sequence where a_{1} = -32 and a_{9} = -120 is -373.

## What is the 32nd term of the arithmetic sequence where a1 14 and a13 − 58?

The 32nd term of the arithmetic sequence where a_{1} = 14 and a_{13} = -58 is a _{32} = -172.

## What is the 32nd term of the arithmetic sequence where a1 =- 33?

The 32nd term of the arithmetic sequence where a_{1} = -33 and a_{9} = -121 is -374.

## What is the 32nd term of the arithmetic sequence where a1?

Ernest Z. The 32nd term of the sequence is −172.

## What is a1 in an arithmetic sequence?

“The nth term of an arithmetic sequence is an = a1 + (n – 1) d, where a1 is the first term and d is the common difference.”

## How do you use the formula a1 + N 1 D?

Step 1: The nth term of an arithmetic sequence is given by an = a + (n – 1)d. So, to find the nth term, substitute the given values a = 2 and d = 3 into the formula. Step 2: Now, to find the fifth term, substitute n = 5 into the equation for the nth term.

## What is the 32nd term of the arithmetic sequence where a1 13 and a13 − 59 1 point?

The 32nd term of the arithmetic sequence where a_{1} = 13 and a_{13} = -59 is -173.

## What is the 32nd term of the arithmetic sequence where a1 12 and a13 − 60?

The 32^{nd} term of the arithmetic sequence where a_{1} = 12 and a_{13} = -60 is -174.

## What is the 32nd te…

Mathematics openstudy (anonymous): What is the 32nd term in the arithmetic series where a1 = –31 and a9 = –119 is the answer to the following question: Still in need of assistance? Join the QuestionCove group and learn while studying with your classmates! Become a member The OpenStudy (amistre64) equation is:a9 = a1 + d (8) solve for d using the information provided in order to determine the 32nd term A32 = a1+d is the answer to OpenStudy (amistre64) (31) What is the answer to OpenStudy’s (anonymous) question?

I received a -339 on OpenStudy (anonymous).

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OpenStudy (amistre64): Thank you for visiting:) Is it -339 for OpenStudy (anonymous)?

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## What is the 32nd term of the arithmetic sequence where a1 = −31 and a9 = −119? −372 −361 −350 −339?

With this one, I’ll be able to claim the title of brainiest. Answers are as follows: 1 It took Alice 5 5/6 hours to travel to her grandparents’ residence for this purpose, according to her. She was stuck in traffic on the way back, and it took her 7 3/8 hours to get home. How much time did it take to get back to the starting point? Write your answer in the simplest form possible, as a correct fraction or mixed number. It took _hours longer to go back home.? Answers are as follows: 1 becca2327, 21st of June, 20:30 UTC, Mathematics Tom works as the deli manager at a local supermarket.

One part-time employee, who works a total of 20 person-hours each week, is employed by Tom.

In order for Tom’s full-time employees to work more than 260 person-hours per week, he must construct an inequality to find n, the maximum number of full-time employees that he may schedule.

Answers are as follows: 2 21st of June, 20:50, kidpryo1 in mathematics There are three bags: a (which includes two white and four red balls), b (which contains eight white and four red balls), and c (which contains eight white and four red balls) (1 white 3 red).

The likelihood that you chose a white ball from bag an is what you should calculate. Answers: 1Do you know what the correct answer is? Is there a 32nd term in the arithmetic series where a1 = 31 and a9 = 119? 372, 361, 350, 339

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## What is the 32nd term of the arithmetic sequence where a1 = –31 and a9 = –119?

ANSWER(S) Because you add 9 over 6 and then divide by 6a, you get 1.5 pounds. add a picture an outline of the steps to take: 3, 12, 48, 384, 1536, 6144, 24576, 98304 are the numbers 3, 12, 48, 384, 1536, 6144, 24576, 98304 are the numbers 3, 12, 48, 384, 1536, 6144, 24576, 98304 step-by-step explanation: simply keep time it by 4 until you get it right. The following formula is used to find the nth term in an arithmetic sequence: To find the nth term in an arithmetic sequence, use the formula written as: a = a1 + a2 (n-1) The term an is the nth term in the series, a1 is the first value in the sequence, n is the term position, and d is the common difference To begin, we must compute for d using the values that have been provided above.

a = a1 + a2 (n-1) the d-119 = -31 plus the (9-1)dd = 11 The following is the formula for calculating the 32nd term: a32 = a1 plus a2 (n-1) the value of da32 is -31 plus (32-1).

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## How to find the nth term of an arithmetic sequence – Algebra 1

When considering an arithmetic series, the first term is, and the fifth term is. What is the second slang phrase? The correct response is:Explanation: The formula may be used to determine the common difference. Isandis is the name we use. We now have a problem to solve. The second term is obtained by multiplying the first term by the common difference. When you add up the first three terms of an arithmetic series, you get 111; the sum of the fourth term gets you 49. What is the first phrase in the sentence?

- The correct response is:Explanation: Let us consider the common distinction, and let us consider the second term.
- We now know that the second period is 37 days long.
- The most often encountered difference is 6.
- The first character in an arithmetic sequence is.
- The fourth and tenth terms of an arithmetic series are 372 and 888, respectively.
- Let us consider the common difference in the series as our correct answer:Explanation: Then, alternatively, or equivalently, or alternatively, The ninth and tenth terms of an arithmetic series have the numbers 87 and 99, respectively, in their corresponding positions.
- The correct response is:Explanation: It is the difference between the tenth and ninth phrases in the sequence that is the most prevalent difference:.

We put this equal to 87, and then proceed to solve: There are two terms in an arithmetic series that are the eighth and tenth terms, respectively: 87 and 99.

The correct response is: An explanation: The eighth and tenth terms of the series are and, where is the first term and is the common difference between the two terms.

The correct response is: Explanation: We must first discover a rule for this arithmetic series in order to be able to calculate the 100th term.

This is the crux of the matter.

Therefore,.

For the hundredth and last time, Thus To find any term in an arithmetic series, do the following: The first term is, is the number of terms to discover, and is the common difference between the first and last terms in the series Figure out which of the following arithmetic sequence’s 18th term is correct.

- Then, using the formula that was provided before the question, write: To find any term in an arithmetic series, use the following formula:where is the first term, is the number of terms to be found, and is the common difference between the terms in the sequence.
- Then, using the remainder of the equation provided before the question, complete the sentence.
- 1, 5, 9, 13,.
- Explanation: The eleventh term signifies that there are a total of ten intervals between the first term and the eleventh term.

The first of these terms is 1. Each subsequent term rises by a factor of four. The n thterm will be equal to 1 + (n – 1) where n is the number of terms (4). The eleventh term will be 1 + (11 – 1)(4)1 + (10)(4)1 + (10)(4)1 + (40)(4) = 1 + (40) = 41.

## Arithmetic Sequences and Series

HomeLessonsArithmetic Sequences and Series | Updated July 16th, 2020 |

Mathematicians use the letterdwhen referring to these difference for this type of sequence.Mathematicians also refer to generic sequences using the letteraalong with subscripts that correspond to the term numbers as follows:This means that if we refer to the fifth term of a certain sequence, we will label it a 5.a 17is the 17th term.This notation is necessary for calculating nth terms, or a n, of sequences.Thed -value can be calculated by subtracting any two consecutive terms in an arithmetic sequence.where n is any positive integer greater than 1.Remember, the letterdis used because this number is called thecommon difference.When we subtract any two adjacent numbers, the right number minus the left number should be the same for any two pairs of numbers in an arithmetic sequence. To determine any number within an arithmetic sequence, there are two formulas that can be utilized.Here is therecursive rule.The recursive rule means to find any number in the sequence, we must add the common difference to the previous number in this list.Let us say we were given this arithmetic sequence.

First, we would identify the common difference.We can see the common difference is 4 no matter which adjacent numbers we choose from the sequence.To find the next number after 19 we have to add 4.19 + 4 = 23.So, 23 is the 6th number in the sequence.23 + 4 = 27; so, 27 is the 7th number in the sequence, and so on.What if we have to find the 724th term?This method would force us to find all the 723 terms that come before it before we could find it.That would take too long.So, there is a better formula.It is called theexplicit rule.So, if we want to find the 724th term, we can use thisexplicit rule.Our n-value is 724 because that is the term number we want to find.The d-value is 4 because it is thecommon difference.Also, the first term, a 1, is 3.The rule gives us a 724= 3 + (724 – 1)(4) = 3 + (723)(4) = 3 + 2892 = 2895. Each arithmetic sequence has its own unique formula.The formula can be used to find any term we with to find, which makes it a valuable formula.To find these formulas, we will use theexplicit rule.Let us also look at the following examples.Example 1 : Let’s examinesequence Aso that we can find a formula to express its nth term.If we match each term with it’s corresponding term number, we get: The fixed number, which is referred to as the common differenceor d-value, is three.

- We may use this information to replace the explicit rule in the code.
- a n = a 1 + a (n – 1) the value of da n= 5 + (n-1) (3) the number 5 plus 3n – 3a the number 3n + 2a the number 3n + 2 When asked to identify the 37th term in this series, we would compute for a 37 in the manner shown below.
- Exemple No.
- In this case, issequence B.
- a n= 5n + 21a 14= 5(14) + 21a 14= 70 + 21a 14= 91ideo:Finding the nth Term of an Arithmetic Sequence uizmaster:Finding Formula for General Term It may be necessary to calculate the number of terms in a certain arithmetic sequence.

+ 128.In order to use the sum formula.We need to know a few things.We need to know n, the number of terms in the series.We need to know a 1, the first number, and a n, the last number in the series.We do not know what the n-value is.This is where we must start.To find the n-value, let’s use the formula for the series.We already determined the formula for the sequence in a previous section.We found it to be a n= 3n + 2.We will substitute in the last number of the series and solve for the n-value.a n= 3n + 2128 = 3n + 2126 = 3n42 = nn = 42There are 42 numbers in the series.We also know the d = 3, a 1= 5, and a 42= 128.We can substitute these number into the sum formula, like so.S n= (1/2)n(a 1+ a n)S 42= (1/2)(42)(5 + 128)S 42= (21)(133)S 42= 2793This means the sum of the first 42 terms of the series is equal to 2793.Example 2 : Find the sum of the first 205 multiples of 7.First we have to figure out what our series looks like.We need to write multiples of seven and add them together, like this.7 + 14 + 21 + 28 +.

+?To find the last number in the series, which we need for the sum formula, we have to develop a formula for the series.So, we will use theexplicit ruleor a n= a 1+ (n – 1)d.We can also see that d = 7 and the first number, a 1, is 7.a n= a 1+ (n – 1)da n= 7 + (n – 1)(7)a n= 7 + 7n – 7a n= 7nNow we can find the last term in the series.We can do this because we were told there are 205 numbers in the series.We can find the 205th term by using the formula.a n= 7na n= 7(205)a n= 1435This means the last number in the series is 1435.It means the series looks like this.7 + 14 + 21 + 28 +.

+ 1435To find the sum, we will substitute information into the sum formula.

We will substitute a 1= 7, a 205= 1435, and n = 205.S n= (1/2)n(a 1+ a n)S 42= (1/2)(205)(7 + 1435)S 42= (1/2)(205)(1442)S 42= (1/2)(1442)(205)S 42= (721)(205)S 42= 147805This means the sum of the first 205 multiples of 7 is equal to 147,805.