What Is The 22Nd Term Of The Arithmetic Sequence Where A1 = 8 And A9 = 56 134 142 150 158? (Best solution)

Therefore, the 22nd term is 134.

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What is the 24th term of the arithmetic sequence where a1 8 and a9 56 134 140 146 152?

Thus, the 24th term is 146.

What is the 6th term of the geometric sequence where a1?

What is the 6th term of the geometric sequence where a1 = -625 and a2 = 125? Therefore, the 6th term of the geometric sequence is 0.2.

What is the thirty second term?

2: the quotient of a unit divided by 32: one of 32 equal parts of anything one thirty-second of the total.

What is the 24th term of the arithmetic sequence where a1 8 and a9 56?

The 24th term of the arithmetic sequence where a1 = 8 and a9 = 56 is 146.

What is the 6th term of the arithmetic sequence?

Sum = 9a + 45d = 108. Or a + 5d = 12. Hence 6th term = 12. SUFFICIENT.

What kind of sequence is 1 1 1?

Yes, 1,1,1,1 1, 1, 1, 1 is an arithmetic sequence.

What is the 7th term of the geometric sequence?

The nth term of the geometric sequence is given by: an = a · rn 1, Where a is the first term and r is the common ratio respectively. Therefore, the 7th term of the geometric sequence a7 is 1/16.

What is the 32nd term of the arithmetic sequence?

We now apply the formula for the nth term of an arithmetic sequence to determine the 32nd term. tn=a+(n−1)d. t32=−32+(32−1)−11. t32= −32−341. t32=373.

What is the 50th term of the arithmetic sequence?

The 50th term of an arithmetic sequence is 86, and the common difference is 2.

What is the 7th term of the geometric sequence where a1 − 4096 and a4 64?

What is the 7th term of the geometric sequence where a1 = -4,096 and a4 = 64? Summary: The 7th term of the geometric sequence where a1 = -4,096 and a4 = 64 is -1.

What is the 7th term of the geometric sequence where a1 1024 and a4 − 16?

Summary: Given a1 = 1,024 and a4 = -16 the value of the 7th term of the geometric series is 1/4.

What is the sum of the geometric sequence 2 8 32 if there are 8 terms?

The sum of the geometric sequence 2, 8, 32, … if there are 8 terms is 43690.

What is the 22nd te…

Free of charge, you may ask your own question! Mathematics OpenStudy (anonymous): What is the 22nd term of the arithmetic sequence in which a1 = 8 and a9 = 56 is derived from? Join the QuestionCove group and learn while studying with your classmates! To enroll, call 134142150158 or open a study (anonymous): 134142150158. Anonymous OpenStudy participants include: @campbell st @ranga Answers from OpenStudy (anonymous): a22= 134, a41=-145. OpenStudy (campbell st): well, the formula is as follows: you’ll need this to figure out what the common denominator is.

So 56 Equals 16 according to OpenStudy (anonymous) (d) How do you obtain d if you divide both sides?

Fill out the formOpenStudy (campbell st):well you have56 = 8 + 8dsbuttract 8 from both sides of the equation 48 x 8d = 48 x 8d now, find the value of d Study (anonymous): d=6 OpenStudy OpenStudy (campbell st):Yes, you are correct, and you now must As a result, according to OpenStudy (anonymous), a(n)=a1+(n1)d a22=8+(221)d 6 a22 = 8 + 126 a22 = 134 6 a22 = 8 + 126 a22 = 134 Campbell st (OpenStudy): excellent work.

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Join the QuestionCove group and learn while studying with your classmates!

@campbell st Seriously, I had no idea what I was talking about when it came to equations until I got your guidance on this one.

OpenStudy (campbell st): I’m delighted to be of assistance.

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Given The Geometric Sequence Where A1 = 2 And The Common Ratio Is 8, What Is The Domain For N

How many terms are there in the arithmetic sequence where the numbers a1 8 and a9 are 56 134 142 150 158? The 134th term in the arithmetic series is the 22nd term in the sequence. What is the 24th term in the arithmetic series where a1 8 and a9 are 56 134 140 146 and 152?, 1 Answer. As a result, the 24th term is 146. Finally, what is the sixth term of the geometric sequence when a1 128 and a3 8 are both true? The 6th term of this sequence is 0.125, which is a positive number.

Frequently Asked Question:

An explanation: This is an ageometric sequence because each phrase after the first is derived by multiplying a common ratio, r, with the previous term. The most often seen ratio is 4.

What is the common ratio in the geometric sequence?

According to mathematics, ageometric progression, also known as ageometric sequence, is a sequence of positive integers in which each term after the first is obtained by multiplying the preceding one by a fixed, positive number known as the common ratio.

How do you find the common ratio of a geometric sequence of fractions?

Choose any two consecutive terms from thegeometricseries to write down, ideally the first two words.

Take, for instance, if your series is 3/2 + -3/4 + 3/8 + -3/16 +, and your series is 3/2 + 3/8 + -3/16 +. You can use the numbers 3/2 and -3/4. The common ratio may be calculated by dividing the second phrase by the first term.

What is the 23rd term of the arithmetic sequence where a1 8 and a9 48?

Answer: The number 118 represents the 23rd term of A.P. The following is a step-by-step explanation: In light of the fact that the first and ninth terms of the arithmetic sequence are the numbers 8 and 48, respectively.

What is the 22nd term of the arithmetic sequence?

Answer: The 117th term is the 22nd term. The following is the formula for calculating the nth term of an arithmetic sequence: Tn is equal to a + (n – 1)d. In this case, a represents the first term in the series of numbers.

What is the 23rd term of the arithmetic sequence where a1 8 and a9 48?

Answer: The number 118 represents the 23rd term of A.P. The following is a step-by-step explanation: In light of the fact that the first and ninth terms of the arithmetic sequence are the numbers 8 and 48, respectively. (It has been visited 1 time, with 1 visit today)

Given The Arithmetic Sequence An = 2 − 5(N + 1), What Is The Domain For N?

What is the domain of the letter N? Because n is used to count the number of phrases in a sentence, it can only have values that are natural integers. As a result, the domain of n is N, which is the set of natural numbers. What is the 22nd term of the arithmetic sequence consisting of the numbers a1 8 and a9, which is composed of the numbers 134 142 150 158? The 134th term in the arithmetic series is the 22nd term in the sequence. To summarize: What’s the 23rd term in the arithmetic sequence where a1 8 and a9 48 are both true?

The following is a step-by-step explanation: In light of the fact that the first and ninth terms of the arithmetic sequence are the numbers 8 and 48, respectively.

Frequently Asked Question:

Answer: The number 118 represents the 23rd term of A.P. The following is a step-by-step explanation: In light of the fact that the first and ninth terms of the arithmetic sequence are the numbers 8 and 48, respectively.

What is the 25th term of arithmetic sequence?

a25=128. Click here for the answer. Jim G. on July 9, 2018 at a25=128, in

What is the 22nd term of the arithmetic sequence?

Answer: The 117th term is the 22nd term. The following is the formula for calculating the nth term of an arithmetic sequence: Tn is equal to a + (n – 1)d. In this case, a represents the first term in the series of numbers.

What is the 23rd term of the arithmetic sequence where a1 8 and a9 48?

Answer: The number 118 represents the 23rd term of A.P. The following is a step-by-step explanation: In light of the fact that the first and ninth terms of the arithmetic sequence are the numbers 8 and 48, respectively.

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What is the 7th term of the geometric sequence where a1 625 and a2 − 125?

It is the seventh term in the geometric series where a1=– 625 and a2=125 that is equal to –125. (It has been visited 1 time, with 1 visit today)

How to find the nth term of an arithmetic sequence – Algebra 1

When considering an arithmetic series, the first term is, and the fifth term is. What is the second slang phrase? The correct response is:Explanation: The formula may be used to determine the common difference. Isandis is the name we use. We now have a problem to solve. The second term is obtained by multiplying the first term by the common difference. When you add up the first three terms of an arithmetic series, you get 111; the sum of the fourth term gets you 49. What is the first phrase in the sentence?

  1. The correct response is:Explanation: Let us consider the common distinction, and let us consider the second term.
  2. We now know that the second period is 37 days long.
  3. The most often encountered difference is 6.
  4. The first character in an arithmetic sequence is.
  5. The fourth and tenth terms of an arithmetic series are 372 and 888, respectively.
  6. Let us consider the common difference in the series as our correct answer:Explanation: Then, alternatively, or equivalently, or alternatively, The ninth and tenth terms of an arithmetic series have the numbers 87 and 99, respectively, in their corresponding positions.
  7. The correct response is:Explanation: It is the difference between the tenth and ninth phrases in the sequence that is the most prevalent difference:.

We put this equal to 87, and then proceed to solve: There are two terms in an arithmetic series that are the eighth and tenth terms, respectively: 87 and 99.

The correct response is: An explanation: The eighth and tenth terms of the series are and, where is the first term and is the common difference between the two terms.

The correct response is: Explanation: We must first discover a rule for this arithmetic series in order to be able to calculate the 100th term.

This is the crux of the matter.

Therefore,.

For the hundredth and last time, Thus To find any term in an arithmetic series, do the following: The first term is, is the number of terms to discover, and is the common difference between the first and last terms in the series Figure out which of the following arithmetic sequence’s 18th term is correct.

  1. Then, using the formula that was provided before the question, write: To find any term in an arithmetic series, use the following formula:where is the first term, is the number of terms to be found, and is the common difference between the terms in the sequence.
  2. Then, using the remainder of the equation provided before the question, complete the sentence.
  3. 1, 5, 9, 13,.
  4. Explanation: The eleventh term signifies that there are a total of ten intervals between the first term and the eleventh term.

The first of these terms is 1. Each subsequent term rises by a factor of four. The n thterm will be equal to 1 + (n – 1) where n is the number of terms (4). The eleventh term will be 1 + (11 – 1)(4)1 + (10)(4)1 + (10)(4)1 + (40)(4) = 1 + (40) = 41.

Arithmetic Sequences and Series

HomeLessonsArithmetic Sequences and Series Updated July 16th, 2020
Introduction Sequences of numbers that follow a pattern of adding a fixed number from one term to the next are called arithmetic sequences. The following sequences are arithmetic sequences:Sequence A:5, 8, 11, 14, 17,.Sequence B:26, 31, 36, 41, 46,.Sequence C:20, 18, 16, 14, 12,.Forsequence A, if we add 3 to the first number we will get the second number.This works for any pair of consecutive numbers.The second number plus 3 is the third number: 8 + 3 = 11, and so on.Forsequence B, if we add 5 to the first number we will get the second number.This also works for any pair of consecutive numbers.The third number plus 5 is the fourth number: 36 + 5 = 41, which will work throughout the entire sequence.Sequence Cis a little different because we need to add -2 to the first number to get the second number.This too works for any pair of consecutive numbers.The fourth number plus -2 is the fifth number: 14 + (-2) = 12.Because these sequences behave according to this simple rule of addiing a constant number to one term to get to another, they are called arithmetic sequences.So that we can examine these sequences to greater depth, we must know that the fixed numbers that bind each sequence together are called thecommon differences.

Mathematicians use the letterdwhen referring to these difference for this type of sequence.Mathematicians also refer to generic sequences using the letteraalong with subscripts that correspond to the term numbers as follows:This means that if we refer to the fifth term of a certain sequence, we will label it a 5.a 17is the 17th term.This notation is necessary for calculating nth terms, or a n, of sequences.Thed -value can be calculated by subtracting any two consecutive terms in an arithmetic sequence.where n is any positive integer greater than 1.Remember, the letterdis used because this number is called thecommon difference.When we subtract any two adjacent numbers, the right number minus the left number should be the same for any two pairs of numbers in an arithmetic sequence.

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To determine any number within an arithmetic sequence, there are two formulas that can be utilized.Here is therecursive rule.The recursive rule means to find any number in the sequence, we must add the common difference to the previous number in this list.Let us say we were given this arithmetic sequence.

First, we would identify the common difference.We can see the common difference is 4 no matter which adjacent numbers we choose from the sequence.To find the next number after 19 we have to add 4.19 + 4 = 23.So, 23 is the 6th number in the sequence.23 + 4 = 27; so, 27 is the 7th number in the sequence, and so on.What if we have to find the 724th term?This method would force us to find all the 723 terms that come before it before we could find it.That would take too long.So, there is a better formula.It is called theexplicit rule.So, if we want to find the 724th term, we can use thisexplicit rule.Our n-value is 724 because that is the term number we want to find.The d-value is 4 because it is thecommon difference.Also, the first term, a 1, is 3.The rule gives us a 724= 3 + (724 – 1)(4) = 3 + (723)(4) = 3 + 2892 = 2895. Each arithmetic sequence has its own unique formula.The formula can be used to find any term we with to find, which makes it a valuable formula.To find these formulas, we will use theexplicit rule.Let us also look at the following examples.Example 1 : Let’s examinesequence Aso that we can find a formula to express its nth term.If we match each term with it’s corresponding term number, we get: The fixed number, which is referred to as the common differenceor d-value, is three.

  1. We may use this information to replace the explicit rule in the code.
  2. a n = a 1 + a (n – 1) the value of da n= 5 + (n-1) (3) the number 5 plus 3n – 3a the number 3n + 2a the number 3n + 2 When asked to identify the 37th term in this series, we would compute for a 37 in the manner shown below.
  3. Exemple No.
  4. In this case, issequence B.
  5. a n= 5n + 21a 14= 5(14) + 21a 14= 70 + 21a 14= 91ideo:Finding the nth Term of an Arithmetic Sequence uizmaster:Finding Formula for General Term It may be necessary to calculate the number of terms in a certain arithmetic sequence.

+ 128.In order to use the sum formula.We need to know a few things.We need to know n, the number of terms in the series.We need to know a 1, the first number, and a n, the last number in the series.We do not know what the n-value is.This is where we must start.To find the n-value, let’s use the formula for the series.We already determined the formula for the sequence in a previous section.We found it to be a n= 3n + 2.We will substitute in the last number of the series and solve for the n-value.a n= 3n + 2128 = 3n + 2126 = 3n42 = nn = 42There are 42 numbers in the series.We also know the d = 3, a 1= 5, and a 42= 128.We can substitute these number into the sum formula, like so.S n= (1/2)n(a 1+ a n)S 42= (1/2)(42)(5 + 128)S 42= (21)(133)S 42= 2793This means the sum of the first 42 terms of the series is equal to 2793.Example 2 : Find the sum of the first 205 multiples of 7.First we have to figure out what our series looks like.We need to write multiples of seven and add them together, like this.7 + 14 + 21 + 28 +.

+?To find the last number in the series, which we need for the sum formula, we have to develop a formula for the series.So, we will use theexplicit ruleor a n= a 1+ (n – 1)d.We can also see that d = 7 and the first number, a 1, is 7.a n= a 1+ (n – 1)da n= 7 + (n – 1)(7)a n= 7 + 7n – 7a n= 7nNow we can find the last term in the series.We can do this because we were told there are 205 numbers in the series.We can find the 205th term by using the formula.a n= 7na n= 7(205)a n= 1435This means the last number in the series is 1435.It means the series looks like this.7 + 14 + 21 + 28 +.

+ 1435To find the sum, we will substitute information into the sum formula.

We will substitute a 1= 7, a 205= 1435, and n = 205.S n= (1/2)n(a 1+ a n)S 42= (1/2)(205)(7 + 1435)S 42= (1/2)(205)(1442)S 42= (1/2)(1442)(205)S 42= (721)(205)S 42= 147805This means the sum of the first 205 multiples of 7 is equal to 147,805.

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